Optimal. Leaf size=313 \[ \frac {c^6 d^3 x^{m+7} \left (a+b \sinh ^{-1}(c x)\right )}{m+7}+\frac {3 c^4 d^3 x^{m+5} \left (a+b \sinh ^{-1}(c x)\right )}{m+5}+\frac {3 c^2 d^3 x^{m+3} \left (a+b \sinh ^{-1}(c x)\right )}{m+3}+\frac {d^3 x^{m+1} \left (a+b \sinh ^{-1}(c x)\right )}{m+1}-\frac {3 b c d^3 \left (35 m^3+455 m^2+1813 m+2161\right ) x^{m+2} \, _2F_1\left (\frac {1}{2},\frac {m+2}{2};\frac {m+4}{2};-c^2 x^2\right )}{(m+1) (m+2) (m+3)^2 (m+5)^2 (m+7)^2}-\frac {b c d^3 \left (m^4+27 m^3+284 m^2+1329 m+2271\right ) \sqrt {c^2 x^2+1} x^{m+2}}{(m+3)^2 (m+5)^2 (m+7)^2}-\frac {b c^5 d^3 \sqrt {c^2 x^2+1} x^{m+6}}{(m+7)^2}-\frac {b c^3 d^3 (m+9) (2 m+13) \sqrt {c^2 x^2+1} x^{m+4}}{(m+5)^2 (m+7)^2} \]
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Rubi [A] time = 2.17, antiderivative size = 313, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 7, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {270, 5730, 12, 1809, 1267, 459, 364} \[ \frac {3 c^2 d^3 x^{m+3} \left (a+b \sinh ^{-1}(c x)\right )}{m+3}+\frac {3 c^4 d^3 x^{m+5} \left (a+b \sinh ^{-1}(c x)\right )}{m+5}+\frac {c^6 d^3 x^{m+7} \left (a+b \sinh ^{-1}(c x)\right )}{m+7}+\frac {d^3 x^{m+1} \left (a+b \sinh ^{-1}(c x)\right )}{m+1}-\frac {3 b c d^3 \left (35 m^3+455 m^2+1813 m+2161\right ) x^{m+2} \, _2F_1\left (\frac {1}{2},\frac {m+2}{2};\frac {m+4}{2};-c^2 x^2\right )}{(m+1) (m+2) (m+3)^2 (m+5)^2 (m+7)^2}-\frac {b c d^3 \left (m^4+27 m^3+284 m^2+1329 m+2271\right ) \sqrt {c^2 x^2+1} x^{m+2}}{(m+3)^2 (m+5)^2 (m+7)^2}-\frac {b c^3 d^3 (m+9) (2 m+13) \sqrt {c^2 x^2+1} x^{m+4}}{(m+5)^2 (m+7)^2}-\frac {b c^5 d^3 \sqrt {c^2 x^2+1} x^{m+6}}{(m+7)^2} \]
Antiderivative was successfully verified.
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Rule 12
Rule 270
Rule 364
Rule 459
Rule 1267
Rule 1809
Rule 5730
Rubi steps
\begin {align*} \int x^m \left (d+c^2 d x^2\right )^3 \left (a+b \sinh ^{-1}(c x)\right ) \, dx &=\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-(b c) \int \frac {d^3 x^{1+m} \left (\frac {1}{1+m}+\frac {3 c^2 x^2}{3+m}+\frac {3 c^4 x^4}{5+m}+\frac {c^6 x^6}{7+m}\right )}{\sqrt {1+c^2 x^2}} \, dx\\ &=\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-\left (b c d^3\right ) \int \frac {x^{1+m} \left (\frac {1}{1+m}+\frac {3 c^2 x^2}{3+m}+\frac {3 c^4 x^4}{5+m}+\frac {c^6 x^6}{7+m}\right )}{\sqrt {1+c^2 x^2}} \, dx\\ &=-\frac {b c^5 d^3 x^{6+m} \sqrt {1+c^2 x^2}}{(7+m)^2}+\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-\frac {\left (b d^3\right ) \int \frac {x^{1+m} \left (\frac {c^2 (7+m)}{1+m}+\frac {3 c^4 (7+m) x^2}{3+m}+\frac {c^6 (9+m) (13+2 m) x^4}{(5+m) (7+m)}\right )}{\sqrt {1+c^2 x^2}} \, dx}{c (7+m)}\\ &=-\frac {b c^3 d^3 (9+m) (13+2 m) x^{4+m} \sqrt {1+c^2 x^2}}{(5+m)^2 (7+m)^2}-\frac {b c^5 d^3 x^{6+m} \sqrt {1+c^2 x^2}}{(7+m)^2}+\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-\frac {\left (b d^3\right ) \int \frac {x^{1+m} \left (\frac {c^4 (5+m) (7+m)}{1+m}+\frac {c^6 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) x^2}{(3+m) (5+m) (7+m)}\right )}{\sqrt {1+c^2 x^2}} \, dx}{c^3 (5+m) (7+m)}\\ &=-\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) x^{2+m} \sqrt {1+c^2 x^2}}{(3+m)^2 (5+m)^2 (7+m)^2}-\frac {b c^3 d^3 (9+m) (13+2 m) x^{4+m} \sqrt {1+c^2 x^2}}{(5+m)^2 (7+m)^2}-\frac {b c^5 d^3 x^{6+m} \sqrt {1+c^2 x^2}}{(7+m)^2}+\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-\frac {\left (3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right )\right ) \int \frac {x^{1+m}}{\sqrt {1+c^2 x^2}} \, dx}{(1+m) (3+m)^2 (5+m)^2 (7+m)^2}\\ &=-\frac {b c d^3 \left (2271+1329 m+284 m^2+27 m^3+m^4\right ) x^{2+m} \sqrt {1+c^2 x^2}}{(3+m)^2 (5+m)^2 (7+m)^2}-\frac {b c^3 d^3 (9+m) (13+2 m) x^{4+m} \sqrt {1+c^2 x^2}}{(5+m)^2 (7+m)^2}-\frac {b c^5 d^3 x^{6+m} \sqrt {1+c^2 x^2}}{(7+m)^2}+\frac {d^3 x^{1+m} \left (a+b \sinh ^{-1}(c x)\right )}{1+m}+\frac {3 c^2 d^3 x^{3+m} \left (a+b \sinh ^{-1}(c x)\right )}{3+m}+\frac {3 c^4 d^3 x^{5+m} \left (a+b \sinh ^{-1}(c x)\right )}{5+m}+\frac {c^6 d^3 x^{7+m} \left (a+b \sinh ^{-1}(c x)\right )}{7+m}-\frac {3 b c d^3 \left (2161+1813 m+455 m^2+35 m^3\right ) x^{2+m} \, _2F_1\left (\frac {1}{2},\frac {2+m}{2};\frac {4+m}{2};-c^2 x^2\right )}{(1+m) (2+m) (3+m)^2 (5+m)^2 (7+m)^2}\\ \end {align*}
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Mathematica [A] time = 0.49, size = 257, normalized size = 0.82 \[ \frac {x^{m+1} \left (\frac {6 d \left (\frac {4 d^2 \left ((m+2) \left (c^2 m x^2+c^2 x^2+m+3\right ) \left (a+b \sinh ^{-1}(c x)\right )-b c (m+1) x \, _2F_1\left (-\frac {1}{2},\frac {m}{2}+1;\frac {m}{2}+2;-c^2 x^2\right )-2 b c x \, _2F_1\left (\frac {1}{2},\frac {m}{2}+1;\frac {m}{2}+2;-c^2 x^2\right )\right )}{(m+1) (m+2) (m+3)}+\left (c^2 d x^2+d\right )^2 \left (a+b \sinh ^{-1}(c x)\right )-\frac {b c d^2 x \, _2F_1\left (-\frac {3}{2},\frac {m}{2}+1;\frac {m}{2}+2;-c^2 x^2\right )}{m+2}\right )}{m+5}+\left (c^2 d x^2+d\right )^3 \left (a+b \sinh ^{-1}(c x)\right )-\frac {b c d^3 x \, _2F_1\left (-\frac {5}{2},\frac {m}{2}+1;\frac {m}{2}+2;-c^2 x^2\right )}{m+2}\right )}{m+7} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.63, size = 0, normalized size = 0.00 \[ {\rm integral}\left ({\left (a c^{6} d^{3} x^{6} + 3 \, a c^{4} d^{3} x^{4} + 3 \, a c^{2} d^{3} x^{2} + a d^{3} + {\left (b c^{6} d^{3} x^{6} + 3 \, b c^{4} d^{3} x^{4} + 3 \, b c^{2} d^{3} x^{2} + b d^{3}\right )} \operatorname {arsinh}\left (c x\right )\right )} x^{m}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F(-2)] time = 180.00, size = 0, normalized size = 0.00 \[ \int x^{m} \left (c^{2} d \,x^{2}+d \right )^{3} \left (a +b \arcsinh \left (c x \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {a c^{6} d^{3} x^{m + 7}}{m + 7} + \frac {3 \, a c^{4} d^{3} x^{m + 5}}{m + 5} + \frac {3 \, a c^{2} d^{3} x^{m + 3}}{m + 3} + \frac {a d^{3} x^{m + 1}}{m + 1} + \frac {{\left ({\left (m^{3} + 9 \, m^{2} + 23 \, m + 15\right )} b c^{6} d^{3} x^{7} + 3 \, {\left (m^{3} + 11 \, m^{2} + 31 \, m + 21\right )} b c^{4} d^{3} x^{5} + 3 \, {\left (m^{3} + 13 \, m^{2} + 47 \, m + 35\right )} b c^{2} d^{3} x^{3} + {\left (m^{3} + 15 \, m^{2} + 71 \, m + 105\right )} b d^{3} x\right )} x^{m} \log \left (c x + \sqrt {c^{2} x^{2} + 1}\right )}{m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105} - \int \frac {{\left ({\left (m^{3} + 9 \, m^{2} + 23 \, m + 15\right )} b c^{7} d^{3} x^{7} + 3 \, {\left (m^{3} + 11 \, m^{2} + 31 \, m + 21\right )} b c^{5} d^{3} x^{5} + 3 \, {\left (m^{3} + 13 \, m^{2} + 47 \, m + 35\right )} b c^{3} d^{3} x^{3} + {\left (m^{3} + 15 \, m^{2} + 71 \, m + 105\right )} b c d^{3} x\right )} x^{m}}{{\left (m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105\right )} c^{3} x^{3} + {\left (m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105\right )} c x + {\left ({\left (m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105\right )} c^{2} x^{2} + m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105\right )} \sqrt {c^{2} x^{2} + 1}}\,{d x} - \int \frac {{\left ({\left (m^{3} + 9 \, m^{2} + 23 \, m + 15\right )} b c^{8} d^{3} x^{8} + 3 \, {\left (m^{3} + 11 \, m^{2} + 31 \, m + 21\right )} b c^{6} d^{3} x^{6} + 3 \, {\left (m^{3} + 13 \, m^{2} + 47 \, m + 35\right )} b c^{4} d^{3} x^{4} + {\left (m^{3} + 15 \, m^{2} + 71 \, m + 105\right )} b c^{2} d^{3} x^{2}\right )} x^{m}}{{\left (m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105\right )} c^{2} x^{2} + m^{4} + 16 \, m^{3} + 86 \, m^{2} + 176 \, m + 105}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x^m\,\left (a+b\,\mathrm {asinh}\left (c\,x\right )\right )\,{\left (d\,c^2\,x^2+d\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ d^{3} \left (\int a x^{m}\, dx + \int b x^{m} \operatorname {asinh}{\left (c x \right )}\, dx + \int 3 a c^{2} x^{2} x^{m}\, dx + \int 3 a c^{4} x^{4} x^{m}\, dx + \int a c^{6} x^{6} x^{m}\, dx + \int 3 b c^{2} x^{2} x^{m} \operatorname {asinh}{\left (c x \right )}\, dx + \int 3 b c^{4} x^{4} x^{m} \operatorname {asinh}{\left (c x \right )}\, dx + \int b c^{6} x^{6} x^{m} \operatorname {asinh}{\left (c x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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